H(t)=16t^2+100

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Solution for H(t)=16t^2+100 equation: 



(H)=16H^2+100

We move all terms to the left:

(H)-(16H^2+100)=0

We get rid of parentheses

-16H^2+H-100=0

a = -16; b = 1; c = -100;
Δ = b2-4ac
Δ = 12-4·(-16)·(-100)
Δ = -6399
Delta is less than zero, so there is no solution for the equation

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